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Calculate propagation constant, consisting of the attenuation constant and the phase constant of a single T section with and
Note that no matter what values are chosen as long as .Zt Yt = 1 the propagation constant will always be the same.
The attenuation constant is real and is less than 1, while the Phase constant is 0.
It is possible for the phase constant to be zero. An example is seen in this purely resistive network. This network will attenuate an applied signal and the input and output signals will be in phase with each other, hence the phase constant is zero.
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We start with the loop equations. The voltage and current at one end are known and the voltage and current at the other end are to be found.
where Vs and are the sending end voltage and sending end Current respectively and V.R and IR are the receiving end voltage and current respectively.
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Find ABCD values for sections by raising the ABCD matrix to the
power. This mathematically cascades the T sections together.
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By using the values of VS / VR , with output open, from the ABCD matrix, or the value we can calculate the propagation constant for the values of any N, in this case the value of
T sections
This overall propagation constant is the summation of the individual propagation constants or N times the first propagation constant which is times the value of
= N ln(α2) with the cascaded T sections terminated in ZZO .
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We know from many textbooks on transmission engineering that the image impedance and the propagation constant of the line are:
Solving these two equations simultaneously for the impedance and admittance of the line we have the impedance and admittance as functions of the propagation constant and image impedance of the line.
We now determine the numerical values by setting the image impedance (ZZot) and the propagation constant (γt) of a single T section equal to the impedance and the admittance of the line and then finding the corresponding numerical values of impedance ( ZZL) and admittance (YYL) of the line.
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The differential circuit equations for distributed constants of voltage and current of the line are as follows.
These expressions say that the rate of change of voltage and current with respect to N are equal to the current and voltage times the impedance and admittance of the line respectively. They are the fundamental transmission line equations for voltage and current.
From the second order differential equations and from many textbooks we can find a solution of the transmission line equations as:
We will now substitute the values obtained above for ZZL and YYL For the values of ZL and YL . These are the values obtained by using the image impedance and propagation constant of a single T section.
We have the same ABCD electrical values as the cascaded T sections matrix and the Fibonacci and Lucas matrix values only these values are obtained from the equation of the infinitesimal line using N as an integer distance or N as the number of cascaded T sections.
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The differential circuit equations for distributed constants of voltage and current of the line are as follows. Where omega is the radian frequency and L and C are the inductance and capacitance respectively.
Here we have the rate of change of voltage and current with respect to N as functions of current and voltage times the AC series reactance and shunt susceptance and frequency.
From the second order differential equations and from many textbooks we find a solution of the AC transmission line equations as:
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We ask what value of L and C will be equal to our previously computes ZZL and YYL if the frequency is the same for both reactance and susceptance?
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We have the same ABCD electrical values as the cascaded T sections matrix, the Fibonacci and Lucas matrix and our line of distributed constants values, only these AC values are obtained from the equation of the infinitesimal line using N as an integer distance or N as the number of cascaded T sections.
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